AHow to get current IP in Java? -

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i use code current ip:

public string getipaddress() throws nullpointerexception,         malformedurlexception, ioexception {     url whatismyip = new url("http://checkip.amazonaws.com");     bufferedreader in = null;     try {         in = new bufferedreader(new inputstreamreader(                 whatismyip.openstream()));         string ip = in.readline();         return ip;     } {         if (in != null) {             try {                 in.close();             } catch (ioexception e) {                 e.printstacktrace();             }         }     }  }

but return value incorrect.
what's wrong in code?

you can use will's code on thread : getting 'external' ip address in java

he use amazon service "external ip".

here code :

import java.io.bufferedreader; import java.io.ioexception; import java.io.inputstreamreader; import java.net.url;  public class ipchecker {      public static string getip() throws exception {         url whatismyip = new url("http://checkip.amazonaws.com");         bufferedreader in = null;         try {             in = new bufferedreader(new inputstreamreader(                     whatismyip.openstream()));             string ip = in.readline();             return ip;         } {             if (in != null) {                 try {                     in.close();                 } catch (ioexception e) {                     e.printstacktrace();                 }             }         }     } }

all credits goes will.


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