c++ - Sorting names alphabetically using selection sort. -

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okay, posted same question earlier , got on arrays/vectors , on. fixed people told me run issues program gives me bunch of errors. , time, don't see wrong. makes perfect sense me doesn't computer , i'm mere novice.

so here's i'm trying accomplish. reading names file called names.dat , has names saved this:

collins, bill\n smith, bart\n allen, jim\n . . . holland, beth

i'm trying sort these names alphabetically (both ascending , descending order). let alone descending order now, wrote program supposed sort these names in ascending order. keeps spitting out errors don't understand meanings of. don't know if errors coming deque , string i'm trying define, or other parts. here's got far.

#include<iostream> #include<fstream> #include<iomanip> #include<deque>  using namespace std;  const int size = 20; void setascendingsort(string [], int); void displayarray(string [], int);  int main() {     deque<string> names;     ifstream infile;     infile.open("names.dat");     string name;      while(getline(infile, name))     {     names.push_back(name);     }      cout << "the values before selection sort performed are:" << endl;     displayarray(names, size);      setascendingsort(names, size);     cout << "the values after selection sort performed are:" << endl;     displayarray(names, size);      return 0; }  void displayarray(string array[], int elems) {     for(int count = 0; count < elems; count++)     cout << array[count] << " ";     cout << endl; }  void setascendingsort(string array[], int elems) {     int seek = 0;     int mincount;     int minvalue;      (seek = 0; seek < (elems - 1); seek++)     {     mincount = seek;     minvalue = array[seek];      (int index = seek + 1; index < elems; index++)     {         if (array[index] < minvalue)         {         minvalue = array[index];         mincount = index;         }      }      array[mincount] = array[seek];     array[seek] = minvalue;     } }

what kind of mistakes see don't see? i'm beginner programming , appreciate sort of help. in advance!


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