How to populate dependant select menus dynamically using jQuery, PHP and MySQL? -

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i have searched quite bit on here topic. not find solution problem. i'd appreciate lot if me, school project working on.

i have database table ("main_table") , columns including "sector" , "sub_sector". want have 2 select boxes, first 1 load records database in "sector" column , second 1 load records database in "sub_sector" column depending on selection value of first select box. (for example: if select "plastics" on first select box, second select box should updated sub_sector values sector value equal "plastics").

i have managed load options values database first select box when click on selection, not load option second select box. can find codes below. did not put "sector_options.php" below, seems work fine.

index.html shown below:

<script> $(document).ready(function() {   $('#filter_sector') .load('/php/sector_options.php'); //this part works fine - uploads options first select box  $('#filter_sector').change(function() { $('#filter_subsector').load('/php/subsector_options.php?filter_sector=' + $("#filter_sector").val() } //this part not work - no options on second select box ); });  </script>  <body> <div id="sectors"><p>sector:</p> <select id="filter_sector" name="select_sector" multiple="multiple" size="5"> </select>     </div>   <div id="subsectors"><p>sub sector:</p> <select id="filter_subsector" name="select_subsector" multiple="multiple" size="5"> <option value="" data-filter-type="" selected="selected"> -- make choice --</option> </select>  </div>        </body> </html>

sector_options.php shown below:

<?php  $link = mysqli_connect("*******", "*******","******","********") or die (mysql_error());  $query = "select sector main_table ";  $result = mysqli_query($link, $query);  while($row = mysqli_fetch_assoc($result)) { $options .= "<option value=\"".$row['sector']."\">".$row['sector']."</option>\n  "; }  echo $options;  ?>

subsector_options.php shown below:

<?php  $link = mysqli_connect("********", "*****,"*******", "********") or die (mysql_error());  $sectors = $_request['filter_sector'];  $query = "select sub_sector main_table sector='$sectors'";  $result = mysqli_query($link, $query);  while($row = mysqli_fetch_assoc($result)) {$options .= "<option value=\"".$row['sub_sector']."\">".$row['sub_sector']."</option>\n  "; }  echo $options;  ?>

for completeness, solutions were:

  • check how ajax operations doing using browser network monitor
  • load ajax fetcher scripts in browser tag - in many cases render quite happily there, allowing them more debugged
  • ajax scripts return html injection should only return html, , not full html document.

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