c - Given an array of characters, how can i take multiple digits from this array and assign it to an int value? -

so have char array such

char *array = "hello name steven 123*3"; 

and want extract 123 expression , put in int.

i know can like

int firstnum = array[15] - '0'; 

(assuming 1 15th character in array), , give me firstnum = 1.

but able whole 123 number single integer, , im not quite sure how this.

any appreciated

edit: found out called strtol, unsure of how use it.

i'm thinking long numberwanted = strtol(array[15], *p, 10); how let know when stop? or stop once non-int or non-long? , *p?

try using sscanf.

  int n1 = 0, n2 = 0;   char ch = 0;   char *array = "hello name steven 123*3";   sscanf(array, "%*[^0-9] %d %c %d", &n1, &ch, &n2); 

this assumes prefix string never contain digit. if contain digit, read (which assumes data consists of: prefix string, 1 or more digits, 1 character, 1 or more digits.

  int n1 = 0, n2 = 0;   char ch = 0;    char *array = "hello name steven 123*3";   size_t = strlen(array);    while (--i >= 0 && isdigit(array[i]))     ;   sscanf(array+i+1, "%d", &n2);    ch = array[i];    while (--i >= 0 && isdigit(array[i]))     ;   sscanf(array+i+1, "%d", &n1);