javascript - how to open a new window for a specified java code -

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this question has answer here:

i have code below on page. works. can not find out how make open in new window. window.open doesn't work on it. needed.

<form method="post"> <input type="radio" name="button" value="index1.html" checked>this button goes index1.html (default)<br> <input type="radio" name="button" value="index2.html">this button goes index2.html<br>          <input type="radio" name="button" value="index3.html">this button goes index3.html<br> <input type="submit" value="continue">   <script> $(function(){ $("form").submit(function(e) {     e.preventdefault();     window.location = $(this).find('input[type="radio"]:checked').val(); }); }); </script>  </form>

here update should work using window.open:

http://jsfiddle.net/yqlml/

<form method="post">     <input type="radio" name="button" value="http://www.google.com" checked>this button goes index1.html (default)     <br>     <input type="radio" name="button" value="http://www.yahoo.com">this button goes index2.html     <br>     <input type="radio" name="button" value="http://www.stackoverflow.com">this button goes index3.html     <br>     <input type="submit" value="continue"> </form>  <script>     $(function () {         $("form").submit(function (e) {             e.preventdefault();             var url = $(this).find('input[type="radio"]:checked').val();             window.open(url);          });     }); </script>

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