django - How to show haystack query in a different page? -

i've read getting started haystack documentation i'm struggling in how pass queryset results separate page. i've several days trying without results.

i've created own view , form search. called them in search.html template , working ok if show results in there. but, don't how pass results results.html template.

could me define how receive parameters in results view. i'll appreciate much.

views.py

class institutionsearchview(searchview):     __name__ = 'institutionsearchview'     template = 'search/search.html'      def __init__(self, *args, **kwargs):         # needed switch out default form class.         if kwargs.get('form_class') none:             kwargs['form_class'] = institutionsearchform          super(institutionsearchview, self).__init__(*args, **kwargs)   def search(request):     sqs = searchqueryset().facet('type_institution').facet('levels').facet('languages').facet('location')     form = institutionsearchform(request.get)     if form.is_valid():         cd = form.cleaned_data      return institutionsearchview(form_class=institutionsearchform, searchqueryset=sqs)(request)   def results(request, *args, **kwargs):     return render_to_response('search/results.html', locals(),          context_instance=requestcontext(request)) 

urls.py

urlpatterns = patterns('',      url(r'^$',  views.search, name='haystack_search'),     url(r'^results',  views.results, name='results'),) 

search.html

<div class="span12">     <h1>search</h1>      <form method="get" action="{% url 'institution:results' %}" class=".form-search">         <table>            {{ form.as_table }}     </table>     <input type="submit" value="search"> </form> 

results.html

{% if query %}  results {% endif %}