java - Method for checking Mode -

i have method here, checking mode (most frequent element) in array. although there twist need account , i'm not sure how go doing this. example: if array {1,2,2,3,3,5} .. need print out 'nan' , because 2 , 3 both occur 2 times. on how add appreciated.

my code:

  public double mode() {     double maxvalue=0, maxcount=0;     boolean flag=false;      (int = 0; < data.length; ++i)          {             double count = 0;                 (int j = 0; j < data.length; ++j)                      {                         if (data[j]==(data[i])) ++count;                     }                 if (count > maxcount)                 {                         if(count>1)flag = true;                         maxcount = count;                         maxvalue = data[i];                 }         }         if(flag)         {             return maxvalue;         }         else return 0.0;     }  

i suppose current code not giving out result wanted.

here's code snippet updated:

public double mode() {         // sort array         arrays.sort(data);          double maxvalue = 0.0, maxcount = 0.0;         (int = 0; < data.length; ++i) {              // count number of elements same value             int count = 0;             int index = i;               while (index < data.length) {                 if (data[i] == data[index]) {                     count++;                     index++;                 } else {                     break;                 }             }              if (count > maxcount) {                 maxcount = count;                 maxvalue = data[i];             } else if (count == maxcount) {                 maxcount = count;                 maxvalue = 0.0;             }         }          return maxvalue;     } 

then, point call mode(), following:

double m = mode(); system.out.println(m == 0.0 ? "nan" : m);