c - How the expression evaluates? -

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this question has answer here:

can 1 draw precedence tree expression , please explain side effects..values after expression evaluation in c.

int i=-3, j=2, k=0, m; m= ++i || ++j&&++k;

according me output should -2 3 1 1 gnu c compiler printing -2 2 0 1? want know how?

because j won't evaluated due short circuit evaluation:

m= ++i || ++j && ++k;     ↑

at stage, m evaluated 1 regardless of right side of ||. why?

because 1 || anything 1.


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