Passing entire array to the function in C -

i have written program insertion shot following:

int _tmain(int argc, _tchar* argv[]) { int arr[10] = {1,2,3,10,5,9,6,8,7,4}; int value; cin >> value ; int *ptr; ptr = insertionshot(arr); //here im passing whole array binarysearch(arr,value); return 0; }  int * insertionshot(int arr[]) {  //changed after hint (now, fine) int ar[10]; for(int =0;i < 10; i++) {     ar[i] = arr[i]; }  //changed after hint  int arrlength = sizeof(ar)/sizeof(ar[0]); //here array length 1, should 10 for(int = 1; <= arrlength -1 ;a++) {     int b = a;     while(b > 0 && ar[b] < ar[b-1])     {         int temp;         temp = ar[b-1];         ar[b-1] = ar[b];         ar[b] = temp;         b--;     } } return ar;  } 

the problem after passing whole array function, function definition shows 1 element in array , "arraylength" giving 1.

int arr[] in function formal parameter list syntax quirk, processed int *arr. sizeof trick doesn't behave expect.

in c not possible pass arrays value; , furthermore, @ runtime array not remember length.

you include length information passing pointer whole array @ compile time:

int * insertionshot(int (*arr)[10]) 

of course, approach can ever pass array of length 10. if intend able pass arrays of differing length, have pass length parameter.