Reading integers from text files in java and then finding the median -

i'm stuck this, not sure how it.

what want read input set of numbers text file.

for example.

4 1 2 3 4 

the first line contains n, count of numbers. n lines follow.

if n even, -->n/2. in case 4/2 = 2. find 2nd smallest number of list. output.

if n odd, --> n+1/2, , same.

how do this? have far don't know how sort , read array.

i've stumbled way onto this. taking shots in dark.

import java.io.bufferedreader; import java.io.inputstreamreader;  class testclass {      public static void main(string args[]) throws exception {          // read number of data system standard input.          bufferedreader br = new bufferedreader(new inputstreamreader(system.in));         string line = br.readline();         int n = integer.parseint(line);         // median sum          long summedians = 0;          {             int[] myarray = new int[n];             (int = 0; < n; i++) {                 myarray[i] = integer.parseint(br.readline());             }         }          // write output system standard output          system.out.println(summedians % 100000);         system.out.println(myarray);      } } 

you can sort list , find medium

arrays.sort(myarray); // use java collection sort summedians = (n % 2 == 0) ? myarray[n/2] : myarray[(n+1)/2];