Java Regex to extract the Url of hyperlink (not to use Pattern & Matcher) (Java Regex)? -

how capture urlofhref not use pattern & matcher.

i using gwt plaform & doesn't have pattern & matcher.

this code ok, uses pattern & matcher.

public static string gettheurlofhref(string href){     pattern p = pattern.compile("href=\"(.*?)\"");     matcher m = p.matcher(href);     string url = null;     if (m.find()) {         url = m.group(1); // variable should contain link url     }     return url; } 

so how extract url of hyperlink (not use pattern & matcher) (java regex)?

hmm, perhaps remove don't need instead?

public static string gettheurlofhref(string href){     href = href.replaceall("^.*?href=\"", "");        // remove before                                                       // , including href="      string url = test.substring(0,test.indexof('"')); // till                                                       // first " character     return url; } 

ideone demo

i didn't put handle errors. guess add yourself.

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or maybe:

public static string gettheurlofhref(string href){     string url = href.replaceall("^.*?href=\"([^\"]*)\".*", "$1");     return url; }