c++ - Unexpected results from bitwise operation why (1 | 1 & 2) gives 1 instead of 2? -

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cannot simple calculation straight using visual studio 2010

std::cout<<(1 | 1 & 2);      //gives value 1, expecting 2 since 1 | 1 = 2 , & 2   gives 2   std::cout<<( (1 | 1) & 2);   //gives value 0, why different above?

first case:

1 & 2 // since & has higher precedence |

 01 &10 ----  00

and or result 1, 

   1 or 0 -----    1

in second case

1 | 1 

   01 or 01 ----    01

and , result 2, 

   01 &  10 -----    0

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