ios - Finding the position of UIPanGestureRecognizer -

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i have uipangesturerecognizer added view controller. want able swipe go next view controller (kind of camera on ios lockscreen).

my problem don't know how find position of view being panned.

  • if user passes length , lets go want go next view controller.
  • if user hasn't reached length , lets go want view go default state before panned up.

i know locationinview haven't been able work in in scenario.

i know need use uigesturerecognizerstatechanged , uigesturerecognizerstateended these things, don't know how find position , set position. thanks.

here code:

- (void)pangesture:(uipangesturerecognizer *)recognizer{      if (recognizer.state == uigesturerecognizerstatechanged) {          cgpoint t = [recognizer translationinview:self.view];          if (t.y < 0) {             t = cgpointmake(0, t.y);         }         else {             t = cgpointmake(0, t.y);         }          //look @          recognizer.view.center = cgpointmake(recognizer.view.center.x + t.x, recognizer.view.center.y + t.y);         [recognizer settranslation:cgpointmake(0, 0) inview:self.view];      }     else if (recognizer.state == uigesturerecognizerstateended) {          //if view dragged past 100 px - go next view controller, if not go t bottom of screen     } }

you life made harder resetting translationinview each time translation changes. better served storing default / start position when gesture begins , setting new position each time default / start position , combined translationinview of gesture.

in way won't drift due calculation errors , have default / start position can compare against , reset to, if required, when gesture ends.


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