c - for loop for finding smallest element in an Array -

okay program suppose create array size [8] , once printed i'm using loop find smallest number in array. problem i'm having seems stopping @ second element , declaring smallest. can tell me wrong code

#include <stdio.h> #include <stdlib.h> #include <time.h>   void main(int argc, char* argv[]) { const int len = 8; int a[len]; int i;    srand(time(0));  //fill array for(i = 0; < len; ++i) {     a[i] = rand() % 100; }  //print array (i = 0; < len; ++i) {     printf("%d ", a[i]); } printf("\n"); getchar();  int smallest; (i = 1; < len; i++) {     if (a[i] < smallest)         smallest = a[i];     {         printf("the smallest integer %d @ position %d\n", a[i], i);         break;         getchar();      } } } 

there mistakes in code, following :

1-the variable int smallest used before initializing. 2- logic inside last loop wrong.

the right code :

void main(int argc, char* argv[]) {     const int len = 8;     int a[len];     int smallest;     int location =1;     int i;      srand(time(0));      //fill array     for(i = 0; < len; ++i)      {        a[i] = rand() % 100;     }      //print array     (i = 0; < len; ++i)     {       printf("%d ", a[i]);     }     printf("\n");      smallest = a[0];      ( i= 1 ; < len ; i++ )      {         if ( a[i] < smallest )          {            smallest = a[i];            location = i+1;         }     }      printf("smallest element present @ location %d , it's value %d.\n",      location,    smallest );      getch(); }