datetime - Sort dates file python -

i have file contains dates , tasks in form

(datetime.datetime(2014, 5, 20, 0, 0), 'laundry') (datetime.datetime(2014, 6, 1, 0, 0), 'exam ') 

how can display tasks due within date ( ex. due within week ) in format ?

20/05/2014: laundry 

thanks

assuming data list of tuples this:

date_list = [(datetime.datetime(2014, 5, 20, 0, 0), 'laundry'), (datetime.datetime(2014, 6, 1, 0, 0), 'exam '), (datetime.datetime(2014, 4, 20, 0, 0), 'grocery'), (datetime.datetime(2013, 5, 20, 0, 0), 'tv')] 

• you can sorted list based on dates doing:

  sorted_dates = sorted(date_list, key=lambda x: str(x[1]), reverse=true) 

  here, passing string representation of dates key sorted function translates sorting dates sorting of strings. gives you:

  [(datetime.datetime(2013, 5, 20, 0, 0), 'tv'), (datetime.datetime(2014, 5, 20, 0, 0), 'laundry'), (datetime.datetime(2014, 4, 20, 0, 0), 'grocery'), (datetime.datetime(2014, 6, 1, 0, 0), 'exam ')] 

• you can format date in format want, using strftime method:

  formatted_dates = [(item[0].strftime("%d/%m/%y"), item[1]) item in sorted_dates] 

  which gives you:

  [('20/05/13', 'tv'), ('20/05/14', 'laundry'), ('20/04/14', 'grocery'), ('01/06/14', 'exam ')] 

• your final output can obtained looping formatted_dates as:

  for date, task in formatted_dates: print '{}: {}'.format(date, task) 

  which prints

  20/05/13: tv 20/05/14: laundry 20/04/14: grocery 01/06/14: exam 

if data sorted, can skip step 2.

to tasks due in week, make use of combination of timedelta objects , filter function

tasks_in_a_week = filter(lambda x: x[0] > datetime.datetime.now() , x[0] < datetime.datetime.now() + datetime.timedelta(days=7), sorted_dates) 

explanation: datetime.datetime.now() gives todays date. datetime.datetime.now() + datetime.timedelta(days=7) gives date 7 days today. so, above filter function looks date in sorted_dates list falls after today , before 7 days today i.e., in week.