jquery with variable php -

i have code php

        ............................       ..............................         .................         <input type="radio" name="option[<?php echo $option['product_option_id']; ?>]" stock="                   <?php if ($option_value['subtract']) { ?>         <?php if ($option_value['quantity'] >= 3) { ?>           <?php echo $text_in_stock; ?>           <?php } ?>           <?php if ($option_value['quantity'] < 3 && $option_value['quantity'] > 0) { ?>            <?php echo $option_value['quantity']; ?>&nbsp;<?php echo $text_pcs_only; ?>           <?php } ?>        <?php if ($option_value['quantity'] <= 0) { ?>            <?php echo $text_out_of_stock; ?>           <?php } ?>         <?php } ?>           " value="<?php echo $option_value['product_option_value_id']; ?>" id="option-value-<?php echo $option_value['product_option_value_id']; ?>" onchange="recalculateprice();" />           <div class="pippo">         .................       .......         </div> 

then have script

  <script type="text/javascript">    function recalculateprice()  {   var stock = $('#style_stock').attr('stock');  $('input[type=radio]:checked').each(function() {    $('.pippo').hide(); if ($(this).attr('stock') != '<?php echo $text_out_of_stock; ?>') {     $('.pippo').show()     stock = $(this).attr('stock');       } }); 

i need hide div pippo when check option stock = . attr stock in option radio has if .... have insert in row ?

     if ($(this).attr('stock') != '<?php echo $text_out_of_stock; ?>') {             

i can't tell problem here few important notes:- first in php

• try calculate stock value outside input tag stock attribute & echo final value , remove spaces.

• try use "else if" instead of stacking "if" commands , making ambiguity in value (its easier)

second in javascript

• the code have written show ".pippo" div in case if there @ least on radio button attribute stock != out_of_stock need make sure testing changed radio.

• the value of $(this).attr('stock') in case use line directly undefined u didn't define .

• finally calling onchange attribute make problems in page loading , may give error of undefined function

so instead prefer long using jquery attach events through jquery

here full sample of may can use

html

   <div class="pippo">         .................       .......         </div> <input type="radio"  stock="...."  name="opt"> <input type="radio" checked="checked" stock="10" name="opt">  <div id="style_stock" stock="10">stock = 10</div> 

javascript

function recalculateprice(x)  {          if ($(x).attr('stock') != '....') {                         $('.pippo').show();             //put code want          }else{              $('.pippo').hide();             //put code want          } } $("input[type=radio]").change(function(){     recalculateprice(this);                                         });